Find something in Groovy Collection

I likes groovy because you can create such very complex object easy. But, if you want explore them, it can be such a discovery or/and a nightmare …

My initial source code is :

def items = []
def item1 = [key: 1, value: 10, name: "victor"]
items.add item1
// Then add multiple item with the same structure.

How can I found an item in my List of Map ?

def fibList = [1, 1, 2, 3, 5, 8, 13]
fibList.each { println it }  // prints all of the numbers in the list

If you need to find out if any element of the collection meets the condition.

def fibList = [1, 1, 2, 3, 5, 8, 13]
assert fibList.any { it == 3 }
assert fibList.any { it - 2 > 10 }

This is pretty much equivalent to a Java construct

boolean any(List list, Condition cond)
    for (E e : list) {
        if (cond.meets(e)) {
            return true;
        }
    }
    return false;
}

If you need to find out if any element of the collection meets the condition.

def fibList = [1, 1, 2, 3, 5, 8, 13]
assert fibList.every { it > 0 }

This is pretty much equivalent to a Java construct

boolean every(List list, Condition cond)
    for (E e : list) {
        if (!cond.meets(e)) {
            return false;
        }
    }
    return true;
}

If you need to create a new collection that contains each element of the original collection transformed in some way.

def fibList = [1, 1, 2, 3, 5, 8, 13]
assert fibList.collect { it - 1 } == [0, 0, 1, 2, 4, 7, 12]

This is pretty much equivalent to a Java construct

List every(List list, Command command)
    List result = new ArrayList(list.size());
    for (E e : list) {
        result.add(command(e));
    }
    return result;
}

If you need to create a new collection that contains all elements that meet the condition.

def fibList = [1, 1, 2, 3, 5, 8, 13]
assert fibList.findAll { it > 1 && it < 5 } == [2, 3]

This is pretty much equivalent to a Java construct

List findAll(List list, Condition cond)
    List result = new ArrayList(list.size());
    for (E e : list) {
        if (!cond.meets(e)) {
            result.add(e);
        }
    }
    return result;
}

If you need to find first element that matches the condition.

def fibList = [1, 1, 2, 3, 5, 8, 13]
assert fibList.find { it > 1 } == 2

This is pretty much equivalent to a Java construct

E findAll(List list, Condition cond)
    for (E e : list) {
        if (!cond.meets(e)) {
            return e;
        }
    }
    return null;
}

Let's back to my initial problem. I can find what I want by using :

source: http://hanuska.blogspot.com/2008/12/easy-groovy-iteration.html